UArizona Global Campus Offering Vaccination Program Statistical Model

https://www.desmos.com/calculator/nrvxrspove

Use the template to test your data and then click the share button (upper right corner) and post the link to your Desmos data here. Write 1-2 sentences that explains what you found on the graph. (For example, “Based on the data, I am rejecting my hypothesis” or whatever you end up finding.)

DATA:

The study tries to model offering vaccination to all those low-risk individuals younger than a given age (but no younger than two years old) and all low-risk individuals older than a given age while maintaining vaccination of at-risk individuals of any age. The data set used contains the threshold vaccine dose prices for the addition of low-risk vaccination programs.

The data values are shown in the below table

7

11.6

6

11.5

11.49

11.48

Vaccine Dose Price (in £)
12.12
27.84
31.29
27.54
23.34
17.71
16.6
22.16
25.59
26.57
26.44
25.69
24.78
23.85
22.81
21.87
21.12
20.62
20.28
20.01
19.65
19.18
18.53
17.84
17.14
16.46
15.85
15.32
14.87
14.51
14.14
13.75
13.32
12.92
12.59
12.33
12.13
11.98
11.85
11.75
11.6
11.5
11.54
11.51
	11.49
	11.48

Part 2: Test if it is normal. Write a quality paragraph summarizing your findings, include the mean, standard deviation, the IQR, and tell how the data is skewed if it is.

Answer

We are using the first scenario for statistical analysis purposes (as shown in the formatted data). It contains the data for the Standalone young-age-centric program (vaccinate from 2yrs up to age A). There are 50 records in the data set with a mean value of £17.39 and a sample standard deviation of £5.68. The first quartile is £11.95, and the third quartile is £21.94. It indicates that 75% of the sample had a price higher than £11.95, while 25% had a threshold vaccine price higher than £21.94. Thus, the interquartile range is £9.99 (3rd quartile-1st quartile). The skewness of the data set is 0.641, which means it is somewhat positively skewed or skewed to the right. The data cannot be said to be normal due to its positive skewness value.