Thanks for sharing your post, for me it was also difficult to identify many of the smells, evensome that I could identify confused it with something else, I agree with you that there are
strong smells that are easier to identify, the comment you made is easier based on our
experiences to recognize the smells I think it is true, and thanks to the experiment we see the
importance of smell and other senses that help us survive.
w Instructions
Question 1
2.77 pts
Fill in the blank: Given that the mean dollar amount spent on groceries by a couple per week is $150
with a standard deviation of $14, at least ___% of couples spend between $100 and $200 per week
on groceries. Don’t assume anything about the distribution…
○ 99.7%
○ 95%
○ 75%
○ 92.2%
○ 93%
O None of these
Question 2
2.77 ptsO None of these
Question 2
2.77 pts
Researchers have claimed that the average number of headaches per student during a semester of
Statistics is less than or equal to 18. Statistics students believe the average is higher. In a sample of
n= 22 students the mean is 23 headaches with a deviation of 2.1. Which of the following represent
the null and alternative hypotheses necessary to test the students’ belief? Also, state the final
conclusion if we decide that we will reject the null hypothesis.
O Ho H = 18 vs. Ha u 18; The data does not support the student’s claim.
O Ho: < 18 vs. Ha H = 18; The data does not support the student's claim.
O Hoμ 18 vs. Ha: > 18; The data does not support the student’s claim.
O Ho:μ ≥ 18 vs. Ha H < 18; The data supports the student's claim.
Ho: 18 vs. Ha: > 18; The data rejects the student’s claim.
None of the aboveO None of the above
Question 3
When the ….. is sufficiently large, the Central Limit Theorem allows us to assume that
is approx. normally distributed.
Ox, standard deviation
sample size, x-bar
Ox-bar, sample size,
Ox, sample size
Ox-bar, standard deviation
O None of these
Question 4
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What is the proper interpretation of op, the standard error of p-hat?
O It indicates the size of the sample proportion.
It indicates how the sample proportion varies from sample to sample.
It indicates the likelihood that your p-value causes us to commit the type I error.
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2.77 pts
2.77 ptsQuestion 4
What is the proper interpretation of σ, the standard error of p-hat?
O It indicates the size of the sample proportion.
It indicates how the sample proportion varies from sample to sample.
It indicates the likelihood that your p-value causes us to commit the type I error.
It indicates the location of the average sample proportion on the number line.
O None of these
Question 5
2.77 pts
2.77 pts
Female heights have a mean of 64 inches (5 foot 4 inches) and a standard deviation of 2.5 inches.
Which of the following would become true about female heights if the standard deviation was 4
inches instead?
O 5 foot tall women would be more common.
6 foot tall women would be less common.
Women would be more closely clustered around the mean.
There would be more women overall.
None of these are trueQuestion 6
2.77 pts
Solve the problem.
We have created a 95% confidence interval for u with the result (6, 11). What conclusion will we
make if we test Ho: μ = 12 vs. Ha: u 12 at α = 0.05?
O Support the Ha.
O Do not Reject Ho, and do not support H.
O Reject Ho, and support H.
O Fail to reject H₂-
We cannot tell what our decision will be with the information given.
Question 7
3.05 pts
A college planned to construct a 90% confidence interval for the mean science ACT score for all
students at the college. However, they decide to form a 99% confidence interval instead, what effect
will this have on the width (margin of error) of the confidence interval?
If everything else remains the same, the margin of error will be the same regardless of the confidence level.
If everything else remains the same, the 99% confidence interval will have a smaller margin of error.
If the sample size is larger than 30, the margin of error will be the same regardless of the confidence level.
If everything else remains the same, the 99% confidence interval will have a greater margin of error.
None of theseQuestion 8
Find the appropriate critical value (either Za/2 or ta/2)
Confidence level = 99% and n = 25
○ Za/2 = 2.583
O Za/2 = 2.567
ta/2 = 2.492
ta/2 = 2.797
O ta/2 = 2.787
O None of these
Question 9
2.77 pts
2.77 pts
Assume that the data has a normal distribution and the number of observations is greater than
fifty. Find the critical z value used to test a null hypothesis.
a = 0.025 for a test of the hypothesis that the mean is greater than or equal to 98.
-2.326
O±1.645
-1.960
O-1.645
○ 1.960Honorlock Browser Guard™
Question 10
2.77 pts
Assume that the data has a normal distribution and the number of observations is greater than
fifty. Find the critical z value used to test a null hypothesis.
a = 0.1 for a test of μ = 122.
±1.4805
±2.576
±1.645
○ ±2.052
O±2.33
O None of these
Question 11
2.77 pts
If a researcher decides to use a 10% significance level for hypothesis testing instead of a 2% level (so
she has decided to use a larger significance level) and she keeps everything else the same, what
effect will this have on the hypothesis test?
O Both the type I and II error rates will decrease.
Both the type I and II error rates will increase.
O The type I error likelihood will decrease, but the type II error likelihood will increase.
O The type I error likelihood will increase, but the type II error likelihood will decrease.
O None of theseS
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Question 12
2.77 pts
In a poker game there is a 68% chance that you will earn a $100 profit on a certain $20 bet, and
there is a 32% chance you will lose your $20 bet. What is the expected value for this bet?
○ $29
$32.50
○ $61.60
O $74.4
0-$36
O None of these
Question 13
2.77 pts
Solve the problem.
A random sample of 4000 U.S. citizens yielded 2250 who are in favor of gun control legislation. A
99% confidence interval was constructed for the true proportion of people who are in favor of gun
control. The resulting interval was as follows: [0.543, 0.583]. If the Legal Defense Group claims that
the majority of the public supports gun control legislation, does this interval contradict their claim?
◇ Yes, because 51% is outside the interval
No, because the sample size was larger than thirty.
No, because there is a 1% chance the interval doesn’t capture the true proportion.
No, because the interval indicates more than half the public supports gun control.
○ Yes, because the interval indicates that less than 50% of the public support gun control.O Ho: $150
O Ho: μs $150, H₁: μ> $150
Question 18
2.77 pts
A test of sobriety involves measuring the subject’s motor skills. Twenty randomly selected sober
subjects take the test and produce a mean score of 41.0 with a standard deviation of 3.7. At the 0.01
level of significance, test the claim that the true mean score for all sober subjects is equal to 40.0.
Use the traditional method of testing hypotheses. The results for the test turn out to be:
Ho: μ= 40.0. H1: / 40.0. Test statistic: t = 2.42. Critical values: t = -2.861, 2.861. Do not reject Ho
There is not sufficient evidence to warrant rejection of the claim that the mean is equal to 40.0.
If a defense attorney argues the results are flawed because the sample size was too small, is his
argument in anyway valid here?
O No, the sample size is never an issue.
No, because we did not reject the null hypothesis.
Yes, because the test was unable to reject the null hypothesis.
Yes, because we rejected the null hypothesis.
○ We need more information to answer.
Question 19
377D
Question 19
2.77 pts
What is the probability that we commit a type one error during the test of the claim that human hip
widths have a mean equal to 16.2 inches conducted at the 1% sig. level?
exactly 0.01
O less than 1%
at most 0.02
O at least 0.02
exactly 0.02
O at most 0.01
Question 20
2.77 pts
For a test of the hypothesis, us 13.0 at the 4% significance level, what can be said about the
probability of committing the type one error (be brief, but precise)?
O exactly 0.96
at most 0.04
O at least 0.04
exactly 0.04
O at most 0.05O at most 0.05
Question 21
2.77 pts
Express the null hypothesis Ho and the alternative hypothesis H₁ in symbolic form. Use the correct
symbol (μ, p, σ )for the indicated parameter.
A psychologist claims that more than 4.6 percent of the population suffers from professional
problems due to extreme shyness. Use p, the true percentage of the population that suffers from
extreme shyness.
O Ho: p>4.6%
H₁: p ≤ 4.6%
O Ho: p = 4.6%
H₁: p < 4.6%
O Ho: p ≤ 4.6%
H₁: p > 4.6%
O Ho: p < 4.6%
H₁: p ≥ 4.6%
O None of the above
Question 22
2.77 ptsOP-value = 0.9983
OP-value = 0.4983
○ None of these
Question 24
Solve the problem.
2.77 pts
A 90% confidence interval for the average salary of all CEOs in the electronics industry was
constructed using the results of a random survey of 45 CEOs. The interval was ($123,041,
$140,104). To make more useful inferences from the data, it is desired to reduce the width of the
confidence interval. Which of the following will result in a reduced interval width?
Decrease the sample size and decrease the confidence level.
Increase the sample size and decrease the confidence level.
Increase the sample size and increase the confidence level.
Decrease the sample size and increase the confidence level.
D
Question 25
A health insurer suspects that the average fee charged by one particular clinic for a modinol
2.77 ptsporlock Browser Guard™
Decrease the sample size and increase the confidence level.
Question 25
2.77 pts
A health insurer suspects that the average fee charged by one particular clinic for a medical
procedure is higher than $1200. The insurer wants to perform a hypothesis test to determine
whether their suspicion is correct. The hypotheses are:
Ho: μ ≤ $1200
Ha: μ> $1200
Suppose that the test will be conducted at a 5% significance level, and the insurer plans to randomly
sample 50 bills from the clinic. What changes to the test can the insurer make to reduce the
likelihood of committing a Type I error and a Type II error?
O Increase the significance level to 10%
O Lower the significance level to 1%, and reduce the sample size to 36.
Lower the significance level to 1%, while also reducing the population standard deviation.
Increase the significance level to 10%, while keeping the sample size fixed at 50.
O Lower the significance level to 1%, and increase the sample size to 200.
Increase the significance level to 10%, and lower the sample size to 36.
Question 26
2.77 pts
How many tissues should a package of tissues contain? Suppose a random sample of 10,000 people#Apps
TU
DO
406
D
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Question 26
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2.77 pts
How many tissues should a package of tissues contain? Suppose a random sample of 10,000 people
yielded the following data on the number of tissues used during a cold: x = 61, s = 25. We want to
test the claim that u≥ 66. State the correct rejection region when a = 0.05.
O Reject Ho if z> 1.96 or z < -1.96.
Reject Ho if z < -20.
Reject Ho if z> 1.645.
O Reject Ho if z> 1.96.
Reject Ho if z < -1.96.
O Reject Ho if z < -1.645.
Question 27
2.77 pts
A politician claims that for the adult population of one town, the mean annual salary is u = $30,000.
Sample data is collected: n = 47, x = $22,298, and s = $14,200. Use a significance level of a = 0.10
to state the correct rejection region for a test of the claim.
O Reject Ho if z> 1.96 or z < -1.96.
Reject Ho if z < -2.576.
Reject Ho if z> 1.96
Reject Ho if z> 1.645 or z < -1.645.
Reject Ho if z> -1.645.
None of theseQuestion 28
2.77 pts
Solve the problem.
Sales of a new line of athletic footwear are crucial to the success of a company. The company wishes
to estimate the average weekly sales of the new footwear to within $200 with 99% reliability. The
initial sales indicate that the standard deviation of the weekly sales figures is approximately $1100.
How many weeks of data must be sampled for the company to get the information it desires?
O 15 weeks
O 14 weeks
○ 90 weeks
O201 weeks
O 200 weeks
O None of these
Question 29
2.77 pts
For the given hypothesis test, explain the meaning of a Type I error or a Type II error, as specified.Question 29
2.77 pts
For the given hypothesis test, explain the meaning of a Type I error or a Type II error, as specified.
In the past, the mean running time for a certain type of flashlight battery has been 8.4 hours. The
manufacturer has introduced a change in the production method and wants to perform a hypothesis
test to determine whether the mean running time has increased as a result. The hypotheses are:
Ho: μ≤ 8.4 hours
HA: μ> 8.4 hours
Which of the statements below describes a Type II error.
norlock Browser Guard™
The manufacturer will decide the mean battery life is greater than 8.4 hours when in fact it is 8.4 hours.
The manufacturer will decide the mean battery life is greater than 8.4 hours when in fact it is less than 8.4
hours.
O The manufacturer will decide the mean battery life is greater than 8.4 hours when in fact it is greater than 8.4
hours.
O The manufacturer will decide the mean battery life is 8.4 hours when in fact it is greater than 8.4 hours.
The manufacturer will decide the mean battery life is 8.4 hours when in fact it is 8.4 hours.
Question 30
2.77 pts
SAMSUNG24.4 ± 1.794
O24.4 ± 1.691
Question 31
2.77 pts
A large software company gives job applicants a test of programming ability and the mean for that
test has been 160 in the past. Twenty-five job applicants are randomly selected from one large
university and they produce a mean score and standard deviation of 183 and 12, respectively. Use a
0.05 level of significance to test the claim that this sample comes from a population with a mean
score greater than 160.
O Test statistic: = 9.583. Critical value: = 1.711. Reject the null hypothesis.
O Test statistic: = 9.583. Critical value: = 2.064. Reject the null hypothesis.
O Test statistic: = -9.583. Critical value: = 1.711. Do not reject the null hypothesis.
O Test statistic: = -9.583. Critical value: = -2.064. Reject the null hypothesis.
Test statistic: = 9.583. Critical value: = 1.708. Reject the null hypothesis.
○ Test statistic: = 9.583. Critical value: = 1.318. Reject the null hypothesis.
Question 32
2.77 ptsQuestion 33
2.77 pts
If the significance level for a hypothesis test is 0.01 and the p-value for the test ends up being
0.0034, after forming the appropriate conclusion based on the p-value, which possible error could
have be committed, type I or type II.
Since we did not reject the null, we might have committed a type one error.
Since we did not reject the null, we might have committed a type two error.
Since we rejected the null, we might have committed a type one error.
◇ Since we rejected the null, we might have committed a type two error.
D
Question 34
2.77 pts
Find a confidence interval for estimating the population μ.
A laboratory tested 74 chicken eggs and found that the mean amount of cholesterol was 238
milligrams with σ = 16.8 milligrams. Construct a 95% confidence interval for the true mean
cholesterol content, μ, of all such eggs.
234 mg
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