James Madison High School Quadratic Equations and Complex Numbers Questions

The test is 20 questions. I will post some of the questions here and upload the rest them when the teacher approapproved.

Question 1 (5 points)
Solve the quadratic equation x2 – 10x + 14 = -4 by completing the square.
OA) X= 517
B)
x=-577
C)
x= -7 7-15
D) x= 70
Question 2 (5 points)
Solve 7×2 – 3x – 10 = 0 using the quadratic formula.
A) x = 20, -14
B) x= -2, 2017
C
3 1271 3
X= + i, x=
14
14
–
V271
i
14
D) x = -1, 107
Question 3 (5 points)
Solve 5×2 – 2x – 3 = 0 using the quadratic formula.
A)
1. 1141, x=-
X=-
5
1 14
5 5
5
B) x = 1, -375
C)
x= -1,3/5
D) -1 14. x
5 5
+
1
5
14
i
5
Question 4 (5 points)
Solve 2×2 – 3x = 12 using the quadratic formula.
3
187
A)
3 87
X= +
4 4
4
4
B)
3 187 3 87
X= + i, x=– i
4 4
4 4
C)
3 105
X= +
4 4
3 105
X=
4 4
OD)
3
X=
4
105 3
-1, x=
4
4
105
i
4
Question 5 (5 points)
Find the solution(s) of the quadratic equation 2×2 – 3x – 35 = 0.
A) x = 5, -7/2
B) x = 5, -7
C) x= -5,7
D) x= -5,772
Question 6 (5 points)
Solve the quadratic equation x2 – 12x + 23 = 0 by completing the square.
A) x = 13 17
B) x = -6 + 13
C) x = 13-16
D) x = 6 / 13
Question 7 (5 points)
Solve the quadratic equation 2×2 – x = 15 using the quadratic formula.
A) x = -3, x = -5,2
B) x= -5/2, x= 3
C) x = 5/2, x = 3
D) x= -3, x=572
Question 8 (5 points)
Solve the quadratic equation 12×2 – 288 = 0 using the square root method.
A) X= 14
B)
x = +2V6
C) x= 12
D) x= +24
What is the solution to the inequality x2 < 16 - 6x? A) x < -8 and x > 2
B) -8 < X-6 C) -63x34 D) -6